I have a very ugly subroutine full of long formulas I determine using probability trees. It gets especially ugly when the dealer has a 10 or ace up. Dear wiz, How do.

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Blackjack is a game of dynamic probabilities and shifting percentages. When we bet 1 dollar per flip, the equation for how much we expect to.

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When it comes to blackjack, the odds are represented in percentage and they are you have to use the probability formula – the number of ways divided by the.

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For simplicity in calculation, previous analyses of blackjack poker have employed models which employ sampling with replacement. In order to assess what.

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The probabilities you compare to, are derived from the assumptions (under typical US rules), that the dealer doesn't have natural. In a typical.

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For simplicity in calculation, previous analyses of blackjack poker have employed models which employ sampling with replacement. In order to assess what.

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By using dealer probability caching methods and revising the method for recursively generating possible player hands, the estimated calculation.

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A blackjack game has a dealer and one or more players. Let's call p the total probability of winning a pass line bet (so p is the number we are trying to calculate). So we only have to solve the equation $20,p = $9, to get p =

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Card counting techniques cannot however be applied in online blackjack. The formula of probability for obtaining a certain favorable value is similar to that for.

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This article discusses the card game blackjack as played in the casinos derivation of the basic mathematical formulas; Section III discusses the prob- ability the rules required the dealer to stand on two cards, the probabilities for the totals.

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It is more a matter of degree, the more you play the more your results will approach the house edge. The best play for a billion hands is the best play for one hand. Because the sum of a large number of random variables always will approach a bell curve we can use the central limit theorem to get at the answer. When the dealer stands on a soft 17, the dealer will bust about When the dealer hits on a soft 17, the dealer will bust about According to my blackjack appendix 4 , the probability of a net win is However, if we skip ties, the probability is So, the probability of a four wins in a row is 0. From my blackjack appendix 7 we see that each 9 removed from a single deck game increases the house edge by 0. Take the dot product of the probability and expected value over each rank. Go through all ranks, except 8, subtract that card from the deck, play out a hand with that card and an 8, determine the expected value, and multiply by 2. Streaks, such as the dealer drawing a 5 to a 16, are inevitable but not predictable. If there were a shuffle between hands the probability would increase substantially. You are forgetting that there are two possible orders, either the ace or the ten can be first. Multiply this dot product by the probability from step 2. So standing is the marginally better play. There is no sound bite answer to explain why you should hit. This is not even a marginal play. There are 24 sevens in the shoe. Let n be the number of decks. According to my blackjack appendix 4 , the probability of an overall win in blackjack is I'm going to assume you wish to ignore ties for purposes of the streak. It depends on the number of decks. Or does it mean that on any given loss it is a 1 in chance that it was the first of 8 losses coming my way? For the non-card counter it may be assumed that the odds are the same in each new round. Repeat step 3 but multiply by 3 instead of 2. Unless you are counting cards you have the free will to bet as much as you want. Take another 8 out of the deck. The fewer the decks and the greater the number of cards the more this is true. I recently replaced my blackjack appendix 4 with some information about the standard deviation which may help. You ask a good question for which there is no firm answer. Is it that when I sit down at the table, 1 out of my next playing sessions I can expect to have an 8 hand losing streak? I know, I know, its some sort of divine intervention betting system I am talking about and no betting system affects the house edge. Probability of Blackjack Decks Probability 1 4. If you want to deviate from the basic strategy here are some borderline plays: 12 against 3, 12 against 4, 13 against 2, 16 against Deviating on these hands will cost you much less. These expected values consider all the numerous ways the hand can play out. My question though is what does that really mean? In that case, the probability of a win, given a resolved bet, is The probability of winning n hands is a row is 0. For each rank determine the probability of that rank, given that the probability of another 8 is zero. Any basic statistics book should have a standard normal table which will give the Z statistic of 0. It depends whether there is a shuffle between the blackjacks. Since this question was submitted, a player held the dice for rolls on May 23, in Atlantic City. All of this assumes flat betting, otherwise the math really gets messy. Determine the probability that the player will resplit to 3 hands. It took me years to get the splitting pairs correct myself. Your question however could be rephrased as, "what is the value of the ace, given that the other card is not a ten. Following this rule will result in an extra unit once every hands. According to my blackjack appendix 9H the expected return of standing is So my hitting you will save 6. Determine the probability that the player will resplit to 4 hands. From my section on the house edge we find the standard deviation in blackjack to be 1. Resplitting up to four hands is allowed. Multiply dot product from step 11 by probability in step 9. I would have to do a computer simulation to consider all the other combinations. Blackjack is not entirely a game of independent trials like roulette, but the deck is not predisposed to run in streaks. For how to solve the problem yourself, see my MathProblems. I have a very ugly subroutine full of long formulas I determine using probability trees.{/INSERTKEYS}{/PARAGRAPH} So the probability of winning six in a row is 0. What you have experienced is likely the result of some very bad losing streaks. Multiply dot product from step 7 by probability in step 5. The standard deviation of one hand is 1. To test the most likely case to favor hitting, 8 decks and only 3 cards, I ran every possible situation through my combinatorial program. Here is how I did it. Cindy of Gambling Tools was very helpful. When I said the probability of losing 8 hands in a row is 1 in I meant that starting with the next hand the probability of losing 8 in a row is 1 in The chances of 8 losses in a row over a session are greater the longer the session. {PARAGRAPH}{INSERTKEYS}This is a typical question one might encounter in an introductory statistics class. That column seemed to put the mathematics to that "feeling" a player can get. Here is the exact answer for various numbers of decks. So, the best card for the player is the ace and the best for the dealer is the 5. Add values from steps 4, 8, and The hardest part of all this is step 3. I hope this answers your question. As I always say all betting systems are equally worthless so flying by the seat of your pants is just as good as flat betting over the long term. If you were to add a card as the dealer you should add a 5, which increases the house edge by 0. Repeat step 3 but multiply by 4 instead of 2, and this time consider getting an 8 as a third card, corresponding to the situation where the player is forced to stop resplitting. However there are other ways you get four aces in the same hand, for example the last card might be an 8 or 9. It may also be the result of progressive betting or mistakes in strategy. Determine the probability that the player will not get a third eight on either hand. The probability of this is 1 in 5,,, For the probability for any number of throws from 1 to , please see my craps survival tables. There are cards remaining in the two decks and 32 are tens. Thanks for the kind words. Thanks for your kind words. It would take about 5 years playing blackjack 40 hours a week before this piece of advice saved the player one unit. If I'm playing for fun then I leave the table when I'm not having fun any longer. Putting aside some minor effects of deck composition, the dealer who pulled a 5 to a 16 the last five times in a row would be just as likely to do it the next time as the dealer who had been busting on 16 for several hours. What is important is that you play your cards right. Steve from Phoenix, AZ. Besides every once in awhile throwing down a bigger bet just adds to the excitement and for some reason it seems logical that if you have lost a string of hands you are "due" for a win. Expected Values for 3-card 16 Vs. In general the variation in the mean is inversely proportional to the square root of the number of hands you play. I have no problem with increasing your bet when you get a lucky feeling. If the probability of a blackjack is p then the probability of not getting any blackjacks in 10 hands is 1- 1-p For example in a six deck game the answer would be 1- 0. However if you were going to cheat it would be much better to remove an ace, which increases the house edge by 0. The following table displays the results.